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| subject: | ATM Re: Structural truss analysis - initial findings |
From: "Roy Diffrient" To: "ATM" Reply-To: "Roy Diffrient" Tom, I think you're on the right track in using the FEA software to analyze your truss ideas. I have only these few points. - Unless I missed something, there seems to be no allowance for the weight of the truss itself in your examples. Depending on the tubing used, the truss might be as heavy as the load for some of those designs. If there is no way to model that in the software, I'd suggest adding a total of half the calculated truss weight distributed to the total load you have shown, since the CG of all the trusses is apparently at midpoint (the other half of the truss weight is considered to be at the supported end of the truss, where it doesn't cause deflection). Adding in this parameter could very well skew your initial results. It really comes down to stiffness versus weight. - I didn't see the standard truss listed in the results table, but the deflection for that design can be easily calculated, and that could be a good check on the FEA software, setup, etc. The deflection is calculated by the formula W L^3 / (c^2 A E), where W = load (plus half the truss weight, as above), L = truss member length, c = base spacing between members, A = cross sectional area of the material in a member, and E = elasticity modulus (for steel, 30 million psi). - Those apparently useless members of the typical 8-element truss form a parallelogram linkage which nicely keeps the upper end parallel to the primary for all deflections. The purpose of the truss, after all, is to hold the optics in collimation. - For trusses where all sides and elements are equal, like all those shown on your site, the deflection will not vary as the truss is rotated around the optical axis. The deflection of each side due to tension/compression does change depending on the rotation angle, but the vector sum of the deflections remains the same, just as the total load remains the same regardless of rotational changes in tension/compression force vectors in the truss elements. - Don't forget Mark Serrurier's original reason for using his truss design on the Hale telescope: It was not because it was stiff enough (it wasn't). It was (in part) because the two ends of the tube assembly could be designed to have equal deflection. Deflection of the bottom end could thus cancel out the deflection of the top end. There's no reason that principle can't also be applied to your design, especially if you plan to use a truss on both ends. So there's more to it than just truss stiffness. Don't get me wrong - improvement of truss design and stiffness is a noble goal, and our trusses might well be improved or optimized using FEA. But so far, it looks like you're only modeling half of the tube assembly. My $.02 worth. Hope it helps. Roy Diffrient Monkton, MD USA --- BBBS/NT v4.00 MP* Origin: Email Gate (1:379/1.100) SEEN-BY: 633/267 270 @PATH: 379/1 633/267 |
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