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| subject: | Re: Hardy-Weinberg lawt |
"Anon." wrote in message
news:cbpfed$8kv$1{at}darwin.ediacara.org...
> Too much statistics - it simply isn't a distribution in the sense I
> would use the term. The only "frequency distribution" (in the sense
> that I would use the term) would be the tri-nomial distribution with
> cell probabilities {p^2, 2p(1-p), (1-p)^2}.
Bob, you might check your texts. According to what I read, you have
just described a binomial distribution (with n=2). The corresponding
trinomial distribution would have six cells:
( p^2, q^2, r^2, 2pq, 2pr, 2qr) with the constraint that p+q+r=1.
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