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| subject: | Division by time?! |
Hi Eric,
You asked:
EC>using the 'time' structure I have tried to add 59 seconds
EC>onto 2 seconds and I get 61 seconds but how do I push the
EC>60 second bit into the minutes to leave the 1 second bit
EC>in the seconds ?
EC>For example!;
EC>gettime(&t);
EC>t.ti_sec = t.ti_sec + 61;
EC>In the example above the minutes would be incimented by 1
EC>and there would be a remainder in the seconds but my
EC>result would be something ike;
EC>The minutes are now 1: and the seconds are now 72:
EC>\E:>
EC>Can anybody help me?
You have to do it yourself :-(.
t.ti_sec = t.ti_sec + 61;
if (60 <= t.ti_sec)
{
t.ti_sec -= 60;
t.ti_min += 1;
if (60 <= t.ti_min)
{
t.ti_min -= 60;
t.ti_hour += 1;
if (24 <= t.ti_hour)
t.ti_hour -= 24;
}
}
This can be put more compactly as:
if (60 <= (t.ti_sec = t.ti_sec + 61))
{
t.ti_sec -= 60;
if (60 <= (t.ti_min += 1))
{
t.ti_min -= 60;
if (24 <= (t.ti_hour += 1))
t.ti_hour -= 24;
}
}
Be warned that "gettime()" and the "time" structure are
not standard
ANSI C, they are Borland extensions.
All in all, it's much easier if you work with a "time_t" value if you
want to do things like this, as this is in seconds since 00:00:00,
1/1/70 and the conversions to text and the tm structure are standard C
and provided in the compiler library.
EC>Thanking you All in anticipation.
EC>Eric. - 'Who could do with some sort of C tutor!':
There are several of us here in the echo who will tutor you.
George
* SLMR 2.1a * Computers eliminate spare time.
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