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| subject: | #DEFINE(S) |
Picture a function which expects to receive an integer as a formal arguement. Such a beast might have a prototype like: void foo_func(int intvar); Now picture a call to that function where a #define(d) integer variable is passed, like: #define GORTZ 38750; int ramalamadingdong = GORTZ; foo_func(ramalamadingdong); No problem with a 32-bit compiler. When I compile with a 16-bit compiler however, I get a warning: "truncation of constant value" on the line where I call foo_func();. I thought that truncation was something that happened to character arrays, not integers. From the sound of that warning message I would expect ramalamadingdong to equal 3875, not the -5983 I'm expecting (32767 - 38750), Am I expecting the wrong thing? * KWQ/2 1.2i * --- FLAME v1.1* Origin: Port Chicago's Loading Dock - 510-676-5359 (1:161/204) SEEN-BY: 396/1 632/0 371 633/260 267 270 371 634/397 635/506 728 810 639/252 SEEN-BY: 670/218 @PATH: 161/204 42 215/34 270/101 396/1 633/260 635/506 728 633/267 |
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