GW> Hi Frederic,

 GW> You asked:
 
 FT> If the function prototype for puts() is:
 
 FT>     int puts(const char *s);
 
 FT> how can it print the following parameter:
 
 FT>     puts( "Hello world from puts!" );
 
 FT> which is not the value of a pointer to char?

 GW> In this case it is, as in C anything other than an integral data type
 GW> is passed by reference. So in the puts() call the address of the start
 GW> of the string "Hello world from puts!" is used, which is
a "const char
 GW> *" 

   Nope, it's still passed by value, since the argument the function 
   expects to receive is a pointer, in other words, the value of said 
   pointer.  It's semantics, though I like to be able to say, 
   unequivocally, that C always passes by value.  :)
   
... "It compiled?  The first screen came up?  Ship it!" -Bill Gates
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