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echo: c_echo
to: Jasen Betts
from: Neil Heller
date: 2003-02-08 12:04:04
subject: How is memory handled?

I just realized that my original post would have been correct had I made 
the variable:

char * foo[] = {"For", "whom", "the",
"bell", "tolls");

The fun comes in rearranging the words yet keeping the meaning the same 
(although breaking a few rules of English grammar).

JB> char *foo_pointer ="For whom the bell tolls" ;
JB>   if you want a modifiable pointer to a string that should not be
JB>   modified.

The question with which I am interested is what happens to the memory 
used by the array after foo* goes out of scope?

þ CMPQwk 1.42 999

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