JD>DA> JD>The formula for calculation the velocity of any object falling in a
JD>DA> vacuum
JD>DA> JD>on this planet is: 32 feet per second squared times the time that 
the
JD>DA> You both flunk.  :-(  Acceleration is delta-velocity divided by
JD>DA> delta-time.  Delta = change in.  So velocity, when starting from
JD>DA> rest, is merely acceleration times TIME.  There's nothing squared
JD>You are right but I am not wrong. I guess the difference is that I
JD>remembered the damn thing from high school physics. You quoted the 
alculus
JD>derived variation that I didn't get to use until later, much later. For
JD>some reason 32 feet per second per second gravitational constant has been
JD>with me a long time, (kinda like my 03-A3) and I am loath to give it up.
I think I can explain your problem.  There is a formula:
            1
        S = - *G*T^2
            2
Which is the formula you gave.
Now, for reasons best known to themselves, physicists have decreed that
"S" stands -- not for "speed" as you might expect -- but for "distance."
So your formula would measure DROP (if shooting more or less
horizontally) or distance fallen.  If you want the velocity of a falling
object, the formula is:
        V = G*T
("G," as you have guessed, is the gravitational constant, which is, as
you stated, about 32 ft per sec per sec.)
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