Hey, folks- here is a brain teaser which I ran across in college,
and to which I have never heard an answer.  The math whizzes I asked
never did figure this one out.
     I don't know the answer.  I assume it is achieved through calculus,
and the little bones and I don't see eye to eye.
     You are figuring out the volume of a half-a-glass of water.  But 
there's a catch to it.  Take your glass, assumed to be a cylinder with
vertical walls and a flat bottom.  Cut it in half, vertically.  This 
leaves you with two shallow scoop-shaped objects.  Throw one away.
The other will hold water, less than the original glass.  The 
question is this:  what is the maximum amount of water the half-glass 
will hold?
    For those who insist on knowing the size of the cylinder, 
               let D = 2 
                   H = 4.
Though I don't think it's needed to solve the problem.  Intuitively,
I suspect that the volume of the scoop will be a fixed proportion of the
volume of the original cylinder.
     I've wondered about this since 1971.  Your turn.
... Mo-o-m!  She's playing with my head and she won't give it back!
--- Blue Wave/Max v2.12 [NR]
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