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| subject: | Re: ATM Basic Foucault tester |
From: "Bob May" To: "atmlist" Reply-To: "Bob May" The easiest thing is to just setup the tests in a row on top of the tester. This will mean that with a little bit of lateral motion, you can change from one test to another. As to the light sources, the same system of a LED can work for each of them without problems. I tend to work a lot with the ol' wall warts (little power supply thingies that you plug in the wall for a lot of the low power electronic stuff) and have a 9V one for my tester which was setup for a 9V battery. The current for the LED is usually about 20ma (1/1000 amp = 1ma) max although some of the newer ones will take more current. Then find the voltage at which they run at (often something like 1.8V or the such) and you then take those numbers and figure out how much voltage you have to drop across the resistor at the current you want to run the LED at. The simple formula - E = I * R - where E is the voltage desired, I is the current through the resistor and R is the resistance of the resistor. There are standard 20%, 10% and 5% values (this % value is the tolerance for the actual resistance vs. what it is marked for with the cheap easy to find resistors) for the ordinary resistors. Resistors are so cheap (I buy resistors in quantity for less than $.0001 each at work) that shipping will be a lot more than the cost of the resistor so finding the surplus shop or Radio Shack in your area is the best place to buy them. Usually the 1/8th watt size is good enough as the current just isn't that high. If you want to have the ability to reduce the LED brightness, calculate what the resistance needed for 1/2ma of current and choose a pot that has at least that much resistance but not much more and place in series with the resistor selected. Bob May http://nav.to/bobmay bobmay{at}nethere.com NEW! http://bobmay.astronomy.net --- BBBS/NT v4.01 Flag-4* Origin: Email Gate (1:379/100) SEEN-BY: 633/267 270 @PATH: 379/100 1 106/1 2000 633/267 |
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